How to logout from Zoho Desk via SAML

 As standard SAML request logout does not work, you can use OAuth logout URL.


When you try to put standard SAML logout URL, you catch an error:
"The SAML v2 logout request is missing the SAMLRequest parameter."

As a work case, you can use standard AOuth logout URL.

For example, you can get it from Fusion Auth, in "OAuth2 & OpenID Connect Integration details" tab.

Comments

Post a Comment

Popular posts from this blog

Symfony - How to logout locked or banned User automatically

If you want to logout locked or banned User automatically, you need, first of all, add new Listener with onKernelRequest(RequestEvent $event) method. Just FYI, this method Symfony calls every time on every request, so, be careful to use this method. It can shoot yourself in the foot. For example: class SecurityUserListener { public function onKernelRequest(RequestEvent $event) { } } After that, we need to check our User on status: banned or locked (what you need). For this we need to inject Token Storage in class constructor. Token Storage can return User. So, lets do it: class SecurityUserListener { public function __construct(private TokenStorageInterface $tokenStorage) { } public function onKernelRequest(RequestEvent $event) { $user = $this->tokenStorage->getToken()?->getUser(); } } Now, you can examine the user object's status. If it meets your criteria, set the current token to null (indicating no user in the token anymore) and...
Читать далее

Javascript - jQuery - Make menu item Active automatically

There is, as minimum, two ways how to add 'active' class to menu item, to highlight it. First one is on backend side. Second one is on frontend side. Now, I talk about variant with frontend side. So, I choose javascript to decide to add 'active' class to menu item or not. There is a code for this: var pathName = window.location.pathname; // Iterate through each anchor tag within list items $("ul li a").each(function () { // Check if the href attribute matches the current URL if ($(this).attr("href") == pathName) { // If there is a match, traverse up the DOM hierarchy to find the corresponding list item $(this).parents('li').each(function () { // Add the 'active' class to highlight the menu item $(this).addClass("active"); }); } }); This script essentially loops through all anchor "a" tags within list items "li" in the specified unordered list "ul". For each a...
Читать далее

Symfony - How to generate URL without controller or path

If you need to generate URL out of controller, you need to create you own Route with necessary path. $route = new \Symfony\Component\Routing\Route('/calculator/new'); And add this route to Route Collection: $routes = new \Symfony\Component\Routing\RouteCollection(); $routes->add('calculator_new', $route); After that you can generate URL: $generator = new \Symfony\Component\Routing\Generator\UrlGenerator($routes, new \Symfony\Component\Routing\RequestContext()); $url = $generator->generate('calculator_new'); This returns: "/calculator/new" If you need to add any query parameters: $url = $generator->generate('calculator_new', ['width' => 100]); This will return "/calculator/new?width=100" as the generated URL, including the specified query parameter. In summary, by creating a route, adding it to a collection, and using a URL generator, you can easily generate URLs and include additional query parameters...
Читать далее